User Comments - wenshaTim

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wenshaTim

Posted on: Calligraphy Practice
May 30, 2012 at 12:42 PM

中国人的"文房西宝"是:笔、墨、纸、砚。

中国人用它们写毛笔字、画中国画。

砚 (yàn) = inkstone on which to dissolve the inkstick in water.

宝bao4=treasure.

Posted on: Losing and Forgetting
May 7, 2012 at 1:12 PM

我知道了,很清楚,谢谢。

Posted on: Losing and Forgetting
May 6, 2012 at 10:42 AM

I'm thinking of the case of the relationship getting weaker.

Losing a good friend.

(careful about diū jokes)

Posted on: Losing and Forgetting
May 5, 2012 at 4:33 PM

How does one say "lose" in the case of a relationship?

"I don't want to lose you."

Don't worry, you are not going to lose me. I am only going away for a while.

Posted on: Where Do You Work?
April 25, 2012 at 11:25 AM

Neither my ipad2 nor my iphone4 can read them. Neither on the browser, nor with the app.

Posted on: Essential Math Terms
November 28, 2011 at 7:07 PM

I goofed in my cutting and pasting - got an extra 等于 in the translation.

O.K. I got more help from a 中国 数学教授 。 Apparently the word order is wrong.

I now understand it as:

f 这个函数在3 的导数等于

3 加 h 括号平方减3的平方整体除以h 当 h 趋于0 时的极限

等于。。。 。。。

the 括号 tells us that the 3+h is in parentheses.

Is there interest in a group for us weirdos who would like to translate or read math in Chinese. We don't want to frighten the others.

Posted on: Essential Math Terms
November 28, 2011 at 4:57 PM

“the equations say it all!”

yes, but one needs to say the equations, if you are speaking Chinese.

Posted on: Essential Math Terms
November 27, 2011 at 3:16 PM

f zhe4ge han2shu4 zai4 3 de dao3shu4 deng3yu2 h qu1jin1yu2 0 de shi2hou4 (or you can just say "shi2" here ) de ji2xian4 deng3yu2 (3 jia1 h) ping2fang1 jian3qu4 3 de ping2fang1 zheng3ti3 chu2yi3 h deng3yu2 9 jia 6h jia1 h de ping2fang1 etc.

Posted on: Essential Math Terms
November 27, 2011 at 2:47 PM

Here is an attempt at the translation. (I had help)

f 这个函数在 3 的导数等于 h 趋近于0 的时候 的极限

等于 (3加h)的平方减去3的平方 整体除以h

等于

9 加 6h 加 h 平房 减 9 整体除以 h

等于

。。。 。。。

Posted on: Essential Math Terms
November 27, 2011 at 2:10 PM

What you say is true, but it is not f'(x^2).

it is (d/dx)(x^2)

or f'(3) where f(x)=x^2,

f'(x^2)=2(x^2). because, as you say, you first differentiate, then substitute.